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Load an image from a byte array in C#

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To load an image from a byte array, use the CreateGdPictureImageFromByteArray method of the GdPictureImaging class.

This method returns a non-zero GdPicture image identifier (imageID) on success. If it fails, it returns 0 — use GetStat() to view the failure reason.

Overloads:

  • CreateGdPictureImageFromByteArray(byte[] Data)
  • CreateGdPictureImageFromByteArray(byte[] Data, DocumentFormat ImageFormat)

The optional ImageFormat parameter is a member of the DocumentFormat enumeration.

When you no longer need the image resource, release it with the ReleaseGdPictureImage method.

To load an image from a byte array, use the following code:

using GdPicture14;
using System;
using System.IO;


using GdPictureImaging gdpictureImaging = new GdPictureImaging();


// Load bytes from an image file.
byte[] byteArray = File.ReadAllBytes(@"C:\temp\source.jpg");


// Create a GdPicture image from the byte array.
int imageID = gdpictureImaging.CreateGdPictureImageFromByteArray(
    byteArray,
    DocumentFormat.DocumentFormatJPEG);


if (imageID == 0)
{
    Console.WriteLine($"CreateGdPictureImageFromByteArray failed: {gdpictureImaging.GetStat()}");
    return;
}


GdPictureStatus status = gdpictureImaging.SaveAsPNG(imageID, @"C:\temp\output.png");
if (status != GdPictureStatus.OK)
{
    Console.WriteLine($"SaveAsPNG failed: {status}");
}


gdpictureImaging.ReleaseGdPictureImage(imageID);